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4n^2-36n=-56
We move all terms to the left:
4n^2-36n-(-56)=0
We add all the numbers together, and all the variables
4n^2-36n+56=0
a = 4; b = -36; c = +56;
Δ = b2-4ac
Δ = -362-4·4·56
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-20}{2*4}=\frac{16}{8} =2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+20}{2*4}=\frac{56}{8} =7 $
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